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How do you take away the √ ?

You put it to the ² power

Use GEMDAS Backwards

What do you use to solve for x

what is an extraneous solution?

An apparent solution that must be rejected because it does not satisfy the original equation.

2+ square root r = 11

minus 2 on both sides= (square root r) ∧2= (9)∧2 r=81

Solve 2 + √r = 11

2 - 2 + √r = 11 - 2

Solve ³√x - 10 = -3

³√x - 10 + 10 = -3 + 10

((x - 2)∧¾)∧4/3 = 1∧4/3

Solve (x - 2)∧¾ = 1

x=4

x∧2/3 +4=12

(x+9)∧2/3=49

First: Subtract 9 from both sides

81=x²+17

First: Subtract 17 from both sides

Why do you ALWAYS check your answer?

To see if it is an extraneous solution, one that does not satisfy the original equation

Square it

How do you get rid of the square root?

Yes

Can some extraneous solutions sometimes satisfy an equation?